圆中最值的十种求法(Ten methods of finding the best value in a circle).doc
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圆中最值的十种求法(Ten methods of finding the best value in a circle)
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Ten methods of finding the best value in a circle
Experimental junior middle school (223700), Jiangsu County, Siyang province (Zhu Yixin)
Seeking the best value in the circle is a common question in the entrance examination
It is also a hot and difficult problem in the entrance examination
Some students feel helpless about seeking the most valuable question
The main reason is that little is known about the method of seeking the best
The train of thought is not flexible enough
Summarized as follows:
First, we use symmetry to find the best value
Figure 1.: the O radius is 2
A, B, C in the O
OA group of OB
Angle AOC=60 degrees
P is a fixed point on OB
Find the minimum value of PA+PC
[analysis]: AO / O to D extension
Connect CD * O in P
That is, the minimum PA+PC at this time
And the minimum value of PA+PC is equal to the length of the string CD
Solution: to extend the AO * O in D
Connect CD to OB in P
Connect PA
O OE group of CD
Pedal for E
In a OCD
Because of / AOC=60 / D= / C=30 ~ ~ so
In the Rt ODE Delta cos30 = DEG
That is, DE=2 x cos30 degrees = so CD=2DE=2
That is, the minimum value of PA+PC is 2.
Two, use the shortest section of the vertical line for the most value
2. as shown in the Cartesian coordinate system
Coordinate for A (3, 2)
The radius is 1 A
P is a fixed point on the X axis
PQ / A Q to cut
The minimum length of the PQ is
[analysis]: connect AQ, PA
The AQ group of PQ. in Rt Delta PQA
PQ=
The minimum value of the PQ is converted to the minimum value of the PA
According to the vertical line, the minimum minimum value of PA is 2.
Solution: connect PA, QA
Because the A Q PQ cut in PQ AQ so far
In the Rt APQ Delta
PQ2=PA2AQ2
PQ=
Because A (3, 2)
According to the shortest line
So the minimum value of PA is 2
So the minimum value of PQ =?
Three, use the shortest line between two points to find the most value
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