[第四章连续时间系统的复频域分析.ppt

作业(2010-11-23) 交: 4.2 (1)、(3)、(5)、(7)、(9); 4.5 (a)、(b)； 4.6 (3)、(4); 4.8 (2)、(6)、(9)； 看: 4.2 (2)、(4)、(6)、(8)、(10); 4.5 (c)、(d) ； 4.6 (1)、(2); 4.7 (2)、(4); 作业(2010-12-01) 交: 4.13、 4.18。 看: 4.14(1)、(3)。 作业(2010-12-08) 4.20（1）、 4.22（1）、 4.29(2)、(4) 作业(2010-12-14) 做: 4.35 ①加法器: Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. ③初始条件为零的积分器 ②乘法器: Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 初始条件不为零的积分器 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. … Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 7、反馈系统 整个反馈系统的系统函数为 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 4.9 系统的稳定性 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 第一步 把 的所有系数按如下顺序排成两行 构筑Houth---Hurwitz阵列的步骤为 第二步：排列R—H 阵列规则如下： Evaluation o