数字电路习题解答习题解答—组合.ppt

* * (1) F=(A+B)(A B) = A B (2) F=A+ABC+ABC+CB+C B = A+BC+BC (3) F=AB+A B+AB+AB = 0 (5) F=ABCD+ABD+BCD+ABCD+BC = AB+BC+BD (4) F=(A+B+C)(A+B+C) = (A+B)+CC = A+B (6) F=AC+ABC+BC+ABC = BC (7) F=AB+ABC+A(B+AB) = 0 (8) F=(A+B)+(A+B)+ (AB)(AB) = 0 1、用布尔代数化简逻辑函数表达式。 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 2、将下列函数展开为最小项表达式。 (1) F(A,B,C) = A(B+C) = A+BC = Σ(1,4,5,6,7) (2) F(A,B,C,D) = A B+ABD(B+CD) = Σ(4,5,6,7,9,12,14) Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 3、用卡诺图法化简下列各式。 (2) F=ABCD+ABC D+AB+AD+ABC =AB+AD (1) F=AC+ABC+BC +ABC = C 1 1 1 1 1 1 AB CD 00 01 11 10 00 01 11 10 AB C 00 01 11 10 0 1 0 0 0 0 1 1 1 1 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. (3) F=AB+AB+BC+AC = A+B+C AB C 00 01 11 10 0 1 1 1 1 1 1 1 1 4、 用卡诺图法化简下列各式。 AB C 00 01 11 10 0 1 1 1 1 1 1 1 1 (4) F=AB+(A+B)(A+C) +A(A+C) =AB+A(A+C)+B(A+C) = A+B+C Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. (5) F(A,B,C) = Σm (1,3,5,7) = C (6) F(A,B,C,D) = Σm(3,4,5,6,9,10,12,13,14,15) AB C 00 01 11 10 0 1 1 1 1 1 用卡诺图法化简下列各式。 1 1 1 1 1 1 1 1 1 1 AB CD 00 01 11 10 00 01 11 10 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 用卡诺图法化简下列各式。 (7) F(A,B,C,D) = Σm(0,1,2,5,6,7,8,9,13,14) (8) F(A,B,C,D) = Σm(0,13,14,15) + Σφ(1,2,3,9,10,11) 1 1 1 1 1 1 1 1 1 1 AB CD 00 01 11 10 00 01 11 10 Φ 1 Φ Φ 1 Φ Φ 1 Φ 1 AB CD 00 01 11 10 00 01 11 10 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 1-11 利用与非门实现下列函数，并画出逻辑图。 (1) F=ABC+AB