ip规划习题（国外英文资料）.doc

ip规划习题（国外英文资料） 1. Now need subnetting on a local area network (LAN), among them, the first computer, which contains the second subnet contains 260 computers, third subnet contains 62 computers. If you assign the LAN a B class address 128.168.0.0, write your IP address allocation scheme and verify the validity of the proposed LAN. Answer: \ 260 computers need 9 host number, 62 computer need 7 host number, 2 computer need 3 host number. So you can divide it this way: Subnet of 260 hosts: 128.168.0.0/23. There are approximately 2 to the 9-3-260 = 249 IP addresses for free addresses. Subnet of 62 hosts: 128.168.1.0/25. There are two to the 7th - 3-62 = 63 free addresses. Subnet of two hosts: 128.168.1.128/29. There are 8-3-2 = 2 free addresses. Note: 1. Minus 3 is minus the network address, broadcast address, and gateway address. There is a large network that is not used and can be used. This is just the most economical way to divide the economy. The free address block is 128.168.1.136/29 - - 128.168.1.248/29 and 128.168.2.0/23-128.168.254.0/23. The IP address of a host on a C network is 198.123.46.237. If you need to divide the network of the host into four subnets, how do you set the subnet mask A total of 0 comments... answer This is a class C address, according to the division CIDR subnet method, can choose to 27 mask, can be divided into a total of six subnet (can meet your needs, also have the fewest network broadcast), can accommodate 30 hosts per subnet. Specific calculation methods, refer to the following table: The number of network hosts per network of subnet mask network 24, 8, 255.255.255.255.255.255.254 257 255.255.255.128 1.126 266, 255.255.255.192 27, 25, 255.255.224 284, 255.255.255.2414 29, 25, 255.255.248, 30, 6 302, 255.255.255.252.62 31, 255.255.255.254 126 1 This problem is first subnet number, divided into four subnets, 4 into a binary to 100 a total of three, we will in the subnet mask with the host of the top three corresponding position 1, othe