第二阶段：GMAT数学公式汇总.pdf

⎧ ⎧ ⎨ ⎪ ⎨ ⎩ ⎪ ⎩ ⎧ ⎨ ⎩ 1 ⎧ ⎪ ⎨ ⎪ ⎩ ⋅⋅⋅ N 0 1 2 N = { 3⋅⋅⋅} n n n + 1 a b(b ≠ 0) a b(b ≠ 0) a b b a 2k k 2k + 1 k 217 0.217 217 217 ⋅⋅⋅ = 0.217 = 999 235 − 2 233 0.235 353 5 ⋅⋅⋅ = 0.235 = = 990 990 1 ShareWithU尚友论坛原创整理 a a ,a3 ⋅⋅⋅a (n ≥ 2) n d d n n 1, 2 n a a , a3 ⋅⋅⋅ a (n ≥ 2) n n n 1, 2 n a a ,a ⋅⋅⋅a (n ≥ 2) n a a n n 1, 2 3 n a a , a ⋅⋅⋅ a (n ≥ 2) n 1, 2 3 n ± × = = n (n ∈Z , m ∈Z + ) m a + b = b + a ( ) ( a + b + c = a + b + c = a + b + c) a ×b = b × a ( ) a ×b × c = a ×b × c = a × b × c) ( a × (b + c) = a ×b + a × c ( ) a − b × c = a × c − b × c m n m+ n m n mn n n n a a = a a = a ab = a b a m n ∈R ;( ) ;( ) , , m n m a = a n a ∈ , ∈ , , R m Z n ∈Z n ≥ 2 + a ≥ 0 a a a 0 ⎧ ⎪ a = ⎨0 a = 0 ⎪ a a 0 − ⎩ 2 Sh