2015-2016学年黑龙江省哈尔滨第三中学高一上学期期末（模块）考试物理试题 图片版.doc

高学年第考试1.D 2.A 3.D 4.C 5.C 6.A 7.C 8.BCD 9.BD 10.BD 11.CD 12.AD 13.D(3分) 14.C（3分） 15.（1）0.50（3分）（2）加速（2分）（3）AB（3分） 16．解析：(1)根据运动学公式v2－v＝2ax. ·············································2’ 代入数据v0＝20 m/s. ···········································2’ (2)刹车开始后1s的位移 ············································2’ 刹车开始后2s的位移 ············································2’ 最后1s内的位移 ············································1’ ·············································1’ 17．(12分)：v＝g t1 ·············································2’ ·············································2’ 进入液体后：F-mg=ma ·····································2’ a＝ 0＝v－a t2 ··················································2’ ············································2’ 得： h＝············································2’ 18．（共16分，第1问5分；第2问4分；第3问7分求出木板位移得3分，求出木块水平位移得3分，求出木块总位移得4分） ①、木块下滑过程：mgsinα -μ0mgcosα=ma0 ···················································2’ a0=g(sina-μ0cosα)=2.5m/s2 vA2-0=2a0l0 ···················································1’ 得：vA =5.0m/s ···················································2’ ②、滑块在木板上滑行时 m：μ1mg=ma1 得：a1=2m/s2 ···················································1’ M：μ1mg-μ2(m+M)g=Ma2 得：a2=3m/s2 ···················································1’ M、m达到共速的时间为t1有：v2=v1- a1 t1= a2 t2 ···················································1’ 得：v2=3.0m/s， t1=1s ···················································1’ (3)、此过程中各自位移：s1=( v1+ v2) t1/2=4.0m ···················································1’ s2=(0+ v2) t1/2=1.5 m ···················································1’ 共速后滑块与木板以相同的加速度减速运动： μ2(m+M)g=(m+M)a3 得：a1=1m/s2 ···················································1’ 减速位移：0-v22=2 (-a3)s3 得：s3=4.5m ···················································1