虚位移习题解.pdf
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1 ,
l
F
FFD ,FE ,
0 ϕ
B
( ) ( − )
x −a b k x a b
δ F F kδ
D E
l l
b
l
F δx −F δx +Fδx 0 ( 1) y F F
D D E E C D E
D
E C
ϕ F
A
( ) ( ) x
xD l −b cosϕ δxD − l −b sinϕδϕ;
x
( ) ( )
xE l +b cosϕ δxE − l +b sinϕδϕ;
1
x C 2l cosϕ δx C −2l sinϕδϕ.
(1)δϕ
2
F ⎛l ⎞
x a + ⎜ ⎟
k ⎝b⎠
2
F
·
CG EF
,12 Fp
2m 2m 1m 3m
(1)
δrD δrB δrE δθ M
−F δr +F cos 45°⋅δr A
P D EF E (1) D B E 45o C
+Mδθ 0
FEF
1
1
δr 3δθ, δr 4δθ,
E B
δr 2δθ
D
(1)
FEF −0.943kN (
F
) 2m p 2m 1m 3m
δθ M
(2)
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