太原理工大学dsp课程设计.pptx

DSP课程设计;设计题目;设计报告封皮;设计报告内容;求一个角度的正弦值 ;例：求一个角度的正弦值; sin_start: .def sin_startd_coeff .usect coeff,4 .datatable: .word 01C7H ;C1=1/(8*9) .word 030BH ;C2=1/(6*7) .word 0666H ;C3=1/(4*5) .word 1556H ;C4=1/(2*3)d_x .usect sin_vars,1d_squr_x .usect sin_vars,1d_temp .usect sin_vars,1d_sinx .usect sin_vars,1c_l .usect sin_vars,1; .text SSBX FRCT STM #d_coeff, AR5 RPT #3 MVPD #table,*AR5+ STM #d_coeff, AR3 STM #d_x,AR2 STM #c_l,AR4 ST #7FFFH,c_l; SQUR *AR2+,A ;A=x^2ST A,*AR2 ;(AR2)=x^2 ||LD *AR4,B ;B=1MASR *AR2+,*AR3+,B,A ;A=1-x^2/72,T=x^2MPYA A ;A=T*A=x^2(1-x^2/72)STH A,*AR2 ;(d_temp)=x^2(1-x^2/72) MASR *AR2-,*AR3+,B,A ;A=1-X^2/42(1-X^2/72),T=x^2(1-x^2/72); MPYA *AR2+ ;B=x^2(1-x^2/42(1-x^2/72))ST B,*AR2 ;(d_temp)=x^2(1-x^2/42(1-x^2/72))||LD *AR4,B ;B=1MASR *AR2-,*AR3+,B,A ;A=1-x^2/20(1-x^2/42(1-x^2/72)) MPYA *AR2+ ;B=x^2 (1-x^2/20(1-x^2/42(1-x^2/72)))ST B,*AR2 ; (d_temp)=B||LD *AR4,B ;B=1; MASR *AR2-,*AR3+,B,A ;A=1-x^2/6(1-x^2/20(1-x^2/42(1-x^2/72))) MPYA d_x ;B=x(1-x^2/6(1-x^2/20(1-x^2/42(1-x^2/72)))) STH B,d_sinx ;sin(theta) RET .end;MEMORY { PAGE 0: EPROM: org=0E000H, len=1000H VECS: org=0FF80H, len=0080H PAGE 1: SPRAM: org=0060H, len=0020H DARAM: org=0080H, len=0010H };SECTIONS { .text :EPROM PAGE 0 .data :EPROM PAGE 0 STACK :SPRAM PAGE 1 sin_vars :DARAM PAGE 1 coeff :DARAM PAGE 1 .vectors :VECS PAGE 0  }