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无线电波长计算方法.doc

发布:2017-08-02约2.68千字共5页下载文档
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短??波(HF)天线长度计算公式:160M波 1/4波长??例:71.25/1.900 =37.50(m) 1/2波长??例:142.5/1.900 =75.00(m) 5/8波长??例:178 /1.900 = 93.68(m) 3/4波长??例:225 /1.900 =118.42(m) 1/1波长??例:285 /1.900 =150.00(m) 短??波(HF)天线长度计算公式:80M波 1/4波长??例:71.25/3.750=19.00(m) 1/2波长??例:142.5/3.750=38.00(m) 5/8波长??例:178??/3.750 =47.47(m) 3/4波长??例:225??/3.750 =60.00(m) 1/1波长??例:285??/3.750 =76.00(m) 短??波(HF)天线长度计算公式:40M波 1/4波长??例:71.25/7.050 =10.11(m) 1/2波长??例:142.5/7.050 =20.21(m) 5/8波长??例:178 /7.050??=25.25(m) 3/4波长??例:225 /7.050??=31.91(m) 1/1波长??例:285 /7.050??=40.43(m) 短??波(HF)天线长度计算公式:30M波 1/4波长??例:71.25/10.125 =7.04(m) 1/2波长??例:142.5/10.125=14.07(m) 5/8波长??例:178 /10.125 =17.58(m) 3/4波长??例:225 /10.125 =22.22(m) 1/1波长??例:285 /10.125 =28.15(m) 短??波(HF)天线长度计算公式:20M波 1/4波长??例:71.25/14.250 =5.00(m) 1/2波长??例:142.5/14.250=10.00(m) 5/8波长??例:178 /14.250 =12.49(m) 3/4波长??例:225 /14.250 =15.79(m) 1/1波长??例:285 /14.250 =20.00(m) 短??波(HF)天线长度计算公式:17M波 1/4波长??例:71.25/18.110 =3.93(m) 1/2波长??例:142.5/18.110 =7.87(m) 5/8波长??例:178 /18.110??=9.83(m) 3/4波长??例:225 /18.110 =12.42(m) 1/1波长??例:285 /18.110 =15.74(m) 短??波(HF)天线长度计算公式:15M波 1/4波长??例:71.25/21.000 =3.33(m) 1/2波长??例:142.5/21.000 =6.66(m) 5/8波长??例:178 /21.000??=8.32(m) 3/4波长??例:225 /21.000 =10.51(m) 1/1波长??例:285 /21.000 =13.32(m) 短??波(HF)天线长度计算公式:12M波 1/4波长??例:71.25/24.950 =2.86(m) 1/2波长??例:142.5/24.950 =5.71(m) 5/8波长??例:178 /24.950??=7.13(m) 3/4波长??例:225 /24.950??=9.02(m) 1/1波长??例:285 /24.950 =11.42(m) 短??波(HF)天线长度计算公式:10M波 1/4波长??例:71.25/29.600 =2.41(m) 1/2波长??例:142.5/29.600 =4.81(m) 5/8波长??例:178 /29.600??=6.01(m) 3/4波长??例:225 /29.600??=7.60(m) 1/1波长??例:285 /29.600??=9.63(m) 短??波(HF)天线长度计算公式:6M波 1/4波长??例:71.25/50.200 = 1.42(m) 1/2波长??例:142.5/50.200 = 2.84(m) 5/8波长??例:178??/50.200 = 3.55(m) 3/4波长??例:225??/50.200 = 4.48(m) 1/1波长??例:285??/50.200 = 5.68(m) 天线的最佳长度及计算方法ZT 天线的最佳长度及计算方法 ? ?一段金属导线中的交变电流能够向空间发射交替变化的感应电场和感应磁场,这就是无线电信号的发射。相反,空间中交变的电磁场在遇到金属导线时又可以感应出交变的电流,这对应了无线信号的接收。 ? ?在电台进行发射和接收时都希望导线中的交变电流能够有效的转换成为空间中的电磁波,或空间中的电磁波能够最有效的转换成导线中的交变电流。这就对用
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