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16G101系列钢筋平法工程图文之详解.ppt

发布:2019-10-19约3.2万字共204页下载文档
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* * * * * * * * * * * * * * 400 400 250 250 250 250 12500 3600 3600 4800 KL1(3)350*500 A8@100/150(4) 2B25 G2B16 4B25 4B25 6B25 4/2 6B25 4/2 (2B16) 6B25 2/4 4B25 4B25 1# 2# 2# 3# 3# 4# 5# 5# 6# 框架梁配筋及钢筋计算演示 7# 7#筋 L=第二跨净长+ max{LaE,0.5hc+5d}*2 =4800-400+ max{1.15*33*25,0.5×400+5×25}×2 =4400+ max{949,325}×2 =4400+1898 =6298mm N=2根 一级抗震 砼C30 HPB300级钢筋基本锚固长度LaE=ξaELa=1.15*35d HRB335级钢筋基本锚固长度LaE=ξaELa=1.15*33d * 400 400 250 250 250 250 12500 3600 3600 4800 KL1(3)350*500 A8@100/150(4) 2B25 G2B16 4B25 4B25 6B25 4/2 6B25 4/2 (2B16) 6B25 2/4 4B25 4B25 8#筋 L=跨净长+15d*2 =12500-500-500+15×16×2 =11500+240×2 =11980mm 1# 2# 2# 3# 3# 4# 5# 5# 6# 框架梁配筋及钢筋计算演示 7# 8# N=2根 一级抗震 砼C30 HPB300级钢筋基本锚固长度LaE=ξaELa=1.15*35d HRB335级钢筋基本锚固长度LaE=ξaELa=1.15*33d * 400 400 250 250 250 250 12500 3600 3600 4800 KL1(3)350*550 A8@100/150(4) 2B25 G2B16 4B25 4B25 6B25 4/2 6B25 4/2 (2B16) 6B25 2/4 4B25 4B25 9#箍筋(大) L=(B+H-4b)*2+1.9d*2+ max{10d,75}*2 = (350+550-4×20)×2+1.9×8×2+ max{10×8,75}*2 =820×2+30.4+80×2 =1640+30.4+160 =1830mm 1# 2# 2# 3# 3# 4# 5# 5# 6# 框架梁配筋及钢筋计算演示 7# 8# 9# 9# 9# 9# N(大)={[(梁高*2-起步距离)/加密区间距+1]*2}*2 ={[(500×2-50)/100+1]×2}×2 ={[10+1]×2}×2={11×2}×2=44根 一级抗震 砼C30 HPB300级钢筋基本锚固长度LaE=ξaELa=1.15*35d HRB335级钢筋基本锚固长度LaE=ξaELa=1.15*33d * 400 400 250 250 250 250 12500 3600 3600 4800 KL1(3)350*550 A8@100/150(4) 2B25 G2B16 4B25 4B25 6B25 4/2 6B25 4/2 (2B16) 6B25 2/4 4B25 4B25 1# 2# 2# 3# 3# 4# 5# 5# 6# 框架梁配筋及钢筋计算演示 7# 8# 9# 9# 9# 9# 9#箍筋(小) L=[(B-2b- 2d-D)/(J-1)*(J`-1)+D+2d]*2+(H-2b)*2 +1.9d*2+max {10d,75}*2 = [(350-2×20 - 2×8-25)/(4-1)×(2-1)+25+2×8]×2 + (550-2×20)×2 +1.9×8×2+max {80,75}*2 = [269/3×1+41]×2+510×2+30.4+80×2 = 261+1020+190 = 1471mm N(小)=44根 一级抗震 砼C30 HPB300级钢筋基本锚固长度LaE
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