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MATLAB程序设计与应用(第三版)刘卫国答案(六).pdf

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MATLAB程序设计与应⽤(第三版)刘卫国答案(六)

第六章MATLAB数据分析于多项式计算

⼀、选题

1~6:CBDDCA

⼆、填空题

1.[15,27,39];[4,5,6]。

2.x^2-1。

3.x=roots(a,b,c);P=poly(x)。

4.⼀维插值;interp1

5.polyfit;polyval。

三、应⽤题

1.

A=randn(10,5)

A=

0.72540.7172-1.06890.3192-1.2141

-0.06311.6302-0.80950.3129-1.1135

0.71470.4889-2.9443-0.8649-0.0068

-0.20501.03471.4384-0.03011.5326

-0.12410.72690.3252-0.1649-0.7697

1.4897-0.3034-0.75490.62770.3714

1.40900.29391.37031.0933-0.2256

1.4172-0.7873-1.71151.10931.1174

0.67150.8884-0.1022-0.8637-1.0891

-1.2075-1.1471-0.24140.07740.0326

(1)

avg=mean(A)%平均值

avg=

0.48280.3542-0.44990.1616-0.1365

sd=std(A)%标准差

sd=

0.87490.86011.33600.69010.9483

(2)

maxA=max(max(A))

maxA=

1.6302

minA=min(min(A))

minA=

-2.9443

(3)

sumArow=sum(A,2)

sumA=

-0.5211

-0.0430

-2.6124

3.7707

-0.0066

1.4304

3.9409

1.1450

-0.4951

-2.4861

sumA=sum(sum(A))

sumA=

4.1228

(4)

sortA=sort(sort(A),2,desend)

sortA=

-0.8649-1.1471-1.2075-1.2141-2.9443

-0.2050-0.7873-0.8637-1.1135-1.7115

-0.1241-0.1649-0.3034-1.0689-1.0891

0.2939-0.0301-0.0631-0.7697-0.8095

0.67150.48890.0774-0.2256-0.7549

0.71720.71470.3129-0.0068-0.2414

0.72690.72540.31920.0326-0.1022

1.40900.88840.62770.37140.3252

1.41721.37031.11741.09331.0347

1.63021.53261.48971.43841.1093

2.

(1)

P1=[3,2];

P2=[5,-1,2];

P3=[1,0,-0.5];

P=onv(onv(P1,P2),P3)

P=poly2str(P,x)

P=

15.00007.0000-3.50000.5000-2.0000-2.0000

P=

’15x^5+7x^4-3.5x^3+0.5x^2-2x-2’

(2)

rs=roots(P)

rs=

0.7071+0.0000i

0.1000+0.6245i

0.1000-0.6245i

-0.7071

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