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万年历程序设计c语言代码.doc

发布:2017-12-17约6.67千字共5页下载文档
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这是当时我做的一个小小的课题,希望对你有所帮助 #include stdio.h /* Required for MS-DOS use */ #define ENTER 0x1C0D /* Enter key */ int year, month, day; static char *days[8] = { ,Sunday ,Monday ,Tuesday , Wednesday,Thursday ,Friday ,Saturday }; struct TIMEDATE { int year; /* year 1980..2099 */ int month; /* month 1=Jan 2=Feb, etc. */ int day; /* day of month 0..31 */ int hours; /* hour 0..23 */ int minutes; /* minute 0..59 */ int seconds; /* second 0..59 */ int hsecs; /* 1/100ths of second 0..99 */ char dateline[47]; /* date time together */ }; static struct TIMEDATE today; main() { char cmonth[3]; char cday[3]; char cyear[5]; double getdays(); double daynumb, numbnow; int weekday, retcode, dayer, i; dayer = datetime(today); clrscn(); for (i=0;i3;++i)cmonth[i]=\0; for (i=0;i3;++i)cday[i]=\0; for (i=0;i5;++i)cyear[i]=\0; putstr(5,8,14,Enter date in MM DD YYYY format:); while (retcode != ENTER) { retcode = bufinp(5,41,13,2,cmonth); if (retcode != ENTER) retcode = bufinp(5,44,13,2,cday); if (retcode != ENTER) retcode = bufinp(5,47,13,4,cyear); } year = atoi(cyear); month = atoi(cmonth); day = atoi(cday); daynumb = getdays(year, month, day); numbnow = getdays(today.year, today.month, today.day); weekday = weekdays(daynumb); if (numbnow - daynumb == 0) printf(\n\n%02d-%02d-%d is,month, day, year); if (numbnow - daynumb 0) printf(\n\n%02d-%02d-%d was,month, day, year); if (numbnow - daynumb 0) printf(\n\n%02d-%02d-%d will be,month, day, year); printf( a %s\n,days[weekday]); } /* end MAIN */ /************************************************************ * GETDAYS - From integer values of year (YYYY), month *
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