java中时间格式的转换.docx

1.将日期类型转换为格式的字符串类型java.util.Date中的日期??? Date Date date = new Date(); ??? SimpleDateFormat sdf = new SimpleDateFormat(yyyy-MM-dd HH:mm:ss);?? ?String time=sdf.format(date);?2.将字符串类型的转换为指定格式的日期类型(java.util.Date) ??? String time = 2009-7-29 14:28:12; ??? DateFormat df = new SimpleDateFormat(yyyy-MM-dd HH:mm:ss);?? ?Date date = df.parse(time); ????这里需要抛出ParseException异常???若将java.util.Date类型转换成java.sql.Date时,只需添加一行代码???java.sql.Date sqlDate = new java.sql.Date(date.getTime()); ?3.使用java.sql.Timestamp在java程序中rs.getDate()时获取日期的时、分、秒? String str = ; ??? String format=yyyy-MM-dd HH:mm:ss; ??? try {????????????? //这里与数据库的连接已经省略,获得PreparedStatement的对象psmt??????????????? ?ResultSet rs = psmt.executeQuery(); ??????????????? while(rs.next()){ ???????????????????? Timestamp ts = rs.getTimestamp(pdate); ?????????????????????SimpleDateFormat sdf = new SimpleDateFormat(format); ???????????????????? str = sdf.format(ts); ??????????????????? System.out.println(str); ?????????????? } ??????? } catch (SQLException e) { ?????????????? e.printStackTrace(); } ......SimpleDateFormat的用法://SimpleDateFormat中的parse方法可以把String型的字符串转换成特定格式的date类型import java.text.*;import java.util.*;public class TestDate {??? public static void main(String[] args) {??????? String dStr = 2001.12.12-08.23.21;??????? Date d = null;??????? SimpleDateFormat sdf = new SimpleDateFormat(yyyy.MM.dd-HH.mm.ss);??????? try {??????????? d = sdf.parse(dStr);??????? } catch (ParseException pe) {??????????? System.out.println(pe.getMessage());??????? }??????? System.out.println(d);??????? System.out.println(d.getTime());??? }}? //下面的format方法可以将date型的数据转换成特定的String型字符串public class FormatDateTime {???? public static void main(String[] args) {???????? SimpleDateFormat myFmt=new SimpleDateFormat(yyyy年MM月dd日 HH时mm分ss秒);???????? SimpleDateFormat myFmt1=new SimpleDateFormat(yy/MM/dd HH:mm);???????? SimpleDateFormat myFmt2=new SimpleDateFormat(yyyy-MM-dd HH:mm:ss);//等价于now.toLocaleString()???????? SimpleDateFormat myFmt3=new SimpleDateF