课程设计二级圆锥-圆柱齿轮减速器设计计算说明书.doc
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湖南大学课程设计 第 页
机械设计基础课程设计
计算说明书
设计题目：二级圆锥-圆柱齿轮减速器
设计者：
学号：
同组者：
学院：
专业班级：
指导教师：
二○一四年○六月二十一日
目 录
一、设计任务书················································································ 2
二、总体设计计算·············································································4
1. 电机型号选择
2. 各级传动比分配
3. 各轴的运动参数和动力参数计算（转速、功率、转矩）
三、传动机构设计计算·····································································6
1. 直齿圆柱传动
2. 圆锥齿轮传动
四、轴系零件设计计算·····································································10
1. 输入轴的设计计算
2. 中间轴的设计计算
3. 输出轴的设计计算
五、滚动轴承的选择与寿命校核计算·············································20
六、 键连接的强度校核计算··························································23
七、润滑和密封方式的选择····························································24
八、箱体的设计···············································································25
九、附件的结构设计和选择····························································25
十、设计总结···················································································26
参考文献··········································??················································27 一、设计任务书
二级圆锥-圆柱设计方案
（1）已知条件：
输送带牵引力F=3500N
带速V=1.7m/s
卷筒直径D=200mm
（2）整体方案如下：
图1-1 二级圆锥-圆柱齿轮减速器整体外观参考图
图1-2 二级圆锥-圆柱齿轮减速器内部结构参考图
图1-3 二级圆锥-圆柱设计运动方案简图
二、总体设计计算
1、电机型号选择
（1）电动机类型选择：Y系列三相异步电动机
（2）电动机功率计算：
输出功率：
P输出= F×V/1000=5.95KW
按《机械设计基础课程设计》P7表2-4 取η联轴器=0.99
轴承的效率的确定：
圆锥齿轮处选用圆锥滚子轴承
直齿圆柱处选用圆锥滚子轴承
按《机械设计基础课程设计》P7表2-4 取η轴承=0.98
圆锥齿轮效率的确定：
按《机械设计基础课程设计》P7表2-4 取η锥齿=0.96
直齿圆柱齿轮效率的确定：
按《机械设计基础课程设计》P7表2-4 取η圆柱=0.97
传动装置的总效率：
η总=η3轴承×η2联轴器×η锥齿×η圆柱
=0.993×0.992×0.95×0.97
=0.85
电机所需的工作功率：
P工作= P输出/η总
=7.02KW
（2）确定电动机转速
卷筒转速：
n筒=60×1000V/πD
=60×1000×1.7/（π×200）
=162.33r/min
按《机械设计基础课程设计》P4表2-1推荐的传动比合理范围，取圆柱齿轮传动一级减速器传动比范围i’a=3~6。取圆锥传动比i’1=2~3，则总传动比理时范围为i’a=6~18。故电动机转速的可选范围为n’d=i’a×n2=（6
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