第四章程序设计部分.ppt

本章作业 * 微机原理与接口技术 * * 第四章 汇编语言程序设计举例 主要内容： 顺序结构程序设计 分支结构程序设计 循环结构程序设计 子程序结构程序设计 顺序结构程序设计 MOV AH,2 MOV DL,AL INT 21H MOV DL,BL INT 21H HLT CODE ENDS END START data1 segment table db 0,1,4,9,16,25,36,49,64,81 buf db Please input one number’ db ‘(0--9):,0Dh,0Ah,$ data1 ends CODE SEGMENT ASSUME CS:code,DS:data1 STRAT: MOV AX,data1 MOV DS,AX MOV BX,OFFSET table MOV DX,OFFSET buf MOV AH,9 INT 21h MOV AH,1 INT 21h PUSH AX MOV AH,2 MOV DL,0DH INT 21H MOV DL,0AH INT 21H POP AX MOV AH,0 AND AL,0fh ADD BX,AX MOV AL,[BX] MOV BL,10 DIV BL ADD AL,30H ADD AH,30H MOV BL,AH ;程序1 :查表求0-9平方值并显示 Data segment Buf db 15 db 31h,00h,47h,60h,00h db 32h,44h,37h,21h,00h db 50h,62h,22h,11h,48h Num db 3 dup(?) Data ends Code segment Main proc far assume cs:code,ds:data start: mov ax,data mov ds,ax mov ch,buf mov bx,1 mov dx,0 lp: mov ah,buf[bx] cmp ah,30h jb next cmp ah,39h ja abc 程序2 （分支结构）分别统计15个字符中‘0～9’和‘A~Z’的个数及其它字符的个数 inc dh jmp next abc:cmp ah,41h jb next cmp ah,5ah ja next inc dl next: inc bx dec ch jnz lp mov buf[bx],dh mov buf[bx+1],dl mov ah,buf sub ah,dh sub ah,dl mov buf[bx+2],ah mov ah,2 mov dl,buf[bx] add dl,30h int 21h mov dl,buf[bx+1] add dl,30h int 21h mov dl,buf[bx+2] add dl,30h int 21h hlt ret main ENDP code ENDS END start CSCODE SEGMENT ASSUME CS:CSCODE MAIN PROC ST