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基于JAVA的违章高发地接口调用代码实例.doc

发布:2017-06-09约4.38千字共4页下载文档
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基于JAVA的违章高发地接口调用代码实例 代码描述:基于JAVA的违章高发地接口调用代码实例 代码平台:聚合数据 import?java.io.BufferedReader; import?java.io.DataOutputStream; import?java.io.IOException; import?java.io.InputStream; import?java.io.InputStreamReader; import?java.io.UnsupportedEncodingException; import?.HttpURLConnection; import?.URL; import?.URLEncoder; import?java.util.HashMap; import?java.util.Map; ? import?net.sf.json.JSONObject; ? /** *违章高发地调用示例代码?-?聚合数据 *在线接口文档:/docs/91 **/ ? public?class?JuheDemo?{ ????public?static?final?String?DEF_CHATSET?=?UTF-8; ????public?static?final?int?DEF_CONN_TIMEOUT?=?30000; ????public?static?final?int?DEF_READ_TIMEOUT?=?30000; ????public?static?String?userAgent?=??Mozilla/5.0?(Windows?NT?6.1)?AppleWebKit/537.36?(KHTML,?like?Gecko)?Chrome/29.0.1547.66?Safari/537.36; ? ????//配置您申请的KEY ????public?static?final?String?APPKEY?=*************************; ? ????//1.检索周边违章高发地 ????public?static?void?getRequest1(){ ????????String?result?=null; ????????String?url?=/wzpoints/query;//请求接口地址 ????????Map?params?=?new?HashMap();//请求参数 ????????????params.put(lat,);//纬度,如:31.335005 ????????????params.put(lon,);//经度,如:120.617183 ????????????params.put(page,);//页数,默认:1 ????????????params.put(pagesize,);//每次返回条数,默认20,最大50 ????????????params.put(r,);//检索半径,默认:500,最大2000 ????????????params.put(key,APPKEY);//应用APPKEY(应用详细页查询) ? ????????try?{ ????????????result?=net(url,?params,?GET); ????????????JSONObject?object?=?JSONObject.fromObject(result); ????????????if(object.getInt(error_code)==0){ ????????????????System.out.println(object.get(result)); ????????????}else{ ????????????????System.out.println(object.get(error_code)+:+object.get(reason)); ????????????} ????????}?catch?(Exception?e)?{ ????????????e.printStackTrace(); ????????} ????} ? ? ? ????public?static?void?main(String[]?args)?{ ? ????} ? ????/** ?????* ?????*?@param?strUrl?请求地址 ?????*?@param?params?请求参数 ?????*?@param?method?请求方法 ?????*?@return??网络请求字符串 ?????*?@throws?Exception ?????*/ ????public?static?String?net(String?strUrl,?Map?para
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