通信电子线路 (谢沅清 邓钢 著) 电子工业出版社 课后答案 04.pdf
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4.3 4-3 1000 kHz
R=1 Ω
4-3 f o=
1000 KH F=1 kHz
( )= (1+ cosΩ )cos
u t U m t t
c a c 4-3
U =10 V
c
m
a U =2
c
2
4 4
m = = = 0.4
a U 10
c
3
Ω=2π 10
课后答案网
3
c=2π 1000 10
3 6
( )=10(1+0.4cos2 10 )cos2 10
u t π t π t
1 2 U2 1 2
Pav=Po 1+ ma = c 1+ ma
2 2R 2
2
10 1 2
= 1+ 0.4 =54 W
2 2
BW=2F=2 kHz
4.4
( )=(8cos200 +cos180 +cos220 ) V
uo t πt πt πt
R=1 Ω
uo (t) f =100 Hz 90 Hz
110 Hz 8 V 1 V
4-4
U2 U2
c SB
P =P +P = + 2
av o SB
2R 2R
2 2
8 1
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