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C语言-分支结构程序设计练习(C language - branch structure programming exercise).doc

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C语言-分支结构程序设计练习(C language - branch structure programming exercise) The program fills in and does not change the statement associated with the input output. Enter a positive integer repeat (0 repeat 10), repeat the following operation: Input parameter a, b, c, solve for a quadratic equation a * x * x + b * x + c = 0 root, and the result is 2 decimal places. The output USES the following statements: Printf ( all parameters are zero, the equation is meaningless! \ n ); Printf ( a and b are 0, c is not 0, the equation is not set \ n ); Printf ( x = % 0.2 f \ n , - c/b); Printf ( x1 = % 0.2 f \ n , (a - b + SQRT (d))/(2 * a)); Printf ( x2 = % 0.2 f \ n , (a - b - SQRT (d))/(2 * a)); Printf ( x1 = % 0.2 f + % 0.2 fi \ n , - b/a) (2 * SQRT (d)/(2 * a)); Printf ( x2 = % % 0.2 f - 0.2 fi \ n , - b/a) (2 * SQRT (d)/(2 * a)); An example of the input output: an illustration in parentheses Input: 5 (repeat = 5) = 0 0 0 0 (a, b = 0, c = 0) = 0 0 0 1 (a, b = 0, c = 1) = 0 0 2 4 (a, b = 2, c = 4) = 2.1 2.1 8.9 3.5 (a, b = 8.9 a, c = 3.5) 1 2 3 (a = 1, b = 2, c = 3) Output: The parameters are zero, the equation is meaningless! A and b are 0, c is not 0, the equation doesnt work X = 2.00 X1 = 0.44 X2 = 3.80 X1 = 1.00 + 1.41 I X2 = - 1.00-1.41 I # include stdio, h H # include math.h Int main (void) { Int repeat, ri; Double a, b, c, d; The scanf ( % d , repeat); For (ri = 1; ri = repeat; r + +) { Lf the scanf ( % % % lf lf , a, b, c); / * -- -- -- -- -- -- -- -- - * / } } # include stdio, h H # include math.h Int main (void) { Int repeat, ri; Double a, b, c, d; The scanf ( % d , repeat); For (ri = 1; ri = repeat; r + +) { Lf the scanf ( % % % lf lf , a, b, c); / * -- -- -- -- -- -- -- -- - * / D = b * * a * b - 4 c. If (a = = 0) If (b = = 0) If (c = = 0) Printf ( all parameters are zero, the equation is meaningless! \ n ); The else printf ( a and b are 0, c is not 0, the equation is not set \ n ); Else printf ( x = % 0.2 f \ n , -c/b); Else if (d = 0) { Printf ( x1
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